Hello!
(Missing Previous Enunciate) Use the Henderson-Hasselbalch equation to find the pH of:
To solve this question we need the pKa of HCOOH, which is 3,75, now, we can apply the Henderson-Hasselbach equation:
[tex]pH=pKa+ log( \frac{[HCOONa]}{[HCOOH]} )=3,75 + log( \frac{0,11M}{0,17M} )=3,56[/tex]
So, the pH of a solution that is 0,17 M in HCHO₂ and 0,11 M in NaCHO₂ is 3,56
Have a nice day!
