Respuesta :

[tex]\bf \textit{lateral area of a cone}\\\\ LA=\pi r\sqrt{r^2+h^2}\quad \begin{cases} r=radius\\ h=height\\ -----\\ r=6\\ h=8 \end{cases}\implies LA=\pi(6)\sqrt{6^2+8^2} \\\\\\ LA=6\pi \sqrt{100}\implies LA=6\pi (10)\implies LA=60\pi [/tex]

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