Respuesta :

Dejanras
Answer is: 50 g of nitrogen has a volume of 40 liters at stp.
m(N₂) = 50 g.
n(N₂) = m(N₂) ÷ M(N₂).
n(N₂) = 50 g ÷ 28 g/mol.
n(N₂) = 1,785 mol.
V(N₂) = n(N₂) · Vm.
V(N₂) = 1,785 mol · 22,4 L/mol.
V = 40 L.
Vm - molare volume on STP.