The mean growth rate shows that the orgasms would double every 47 minutes.
K will be constant. Therefore the population at a time is equal to zero. Then t = 47 and N2 = 2 times N1. N2 is the population later in exponential phase
while N1 is the population earlier in exponential phase. T is the time elapsed btn N1 and N2. The mean growth rate is k = (log2N1 - logN1) or 0.301 times 47 which is equal to 0.0212 minutes.
