snazzydarling snazzydarling
  • 10-01-2018
  • Mathematics
contestada

in rhombus EFGH, if HE = 13 and HP=12,

What is PE?

in rhombus EFGH if HE 13 and HP12What is PE class=

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zhaotianyu369 zhaotianyu369
  • 17-01-2018
PE=5. You need to know an important property of a rhombus: the two diagonals are perpendicular to each other. Angle EPH, same as the other four angles around the center P, is equal to 90 degrees. Since we know HE=13 and HP=12, we use Pythagorean's Theorem to solve for PE=\sqrt(13^2-12^2)=5.
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