claurstmerg
claurstmerg claurstmerg
  • 09-11-2015
  • Mathematics
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3x^2 – 2x + 7 = 0, then (x -1/3)^2

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Benjamin16
Benjamin16 Benjamin16
  • 10-11-2015
[tex]3x^{2} - 2x + 7 = 0 \\ \\ y = (x- \frac{1}{3})^{2} \\ \\ y = x^{2} - \frac{2}{3}x + \frac{1}{9} \\ \\ 3y = 3x^{2} - 2x + \frac{1}{3} \\ \\ 3y = 3x^{2} - 2x + 7 - \frac{20}{3} \\ \\ 3y = 0 - \frac{20}{3} \\ \\ 3y = - \frac{20}{3} \\ \\ \boxed{y =-\frac{20}{9}} [/tex]
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