khalilpeoples5402 khalilpeoples5402
  • 10-11-2017
  • Chemistry
contestada

Calculate the quotient [co32–]/[hco3–] at ph 10.75.

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barnuts
barnuts barnuts
  • 21-11-2017

The chemical equation is:

HCO3^    ->  H^+ + CO3^2- 

 

We know that the formula for Ka is:
Ka = [H^+][CO3^2-]/[HCO3^-] 


log Ka = log[H^+] + log[CO3^2-]/[HCO3^-] 
pKa = pH - log[CO3^2-]/[HCO3^-] 
log[CO3^2-]/[HCO3^-] = pH - pKa = 10.75 - 10.329 = 0.421 
[CO3^2-]/[HCO3^-] = Antilog (0.421)  = 2.636 

 

Answer:

2.636

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