chekashaandrewoz64td chekashaandrewoz64td
  • 09-11-2017
  • Mathematics
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16a^-2b^7c^0/8a^2b^-5

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zrh2sfo zrh2sfo
  • 09-11-2017
Simplify the following:

(16 b^7 c^0 a^2)/(8 a^2 b^5)
(16 b^7 c^0 a^2)/(a^2 b^5×8) = a^2/a^2×(16 b^7 c^0)/(b^5×8) = (16 b^7 c^0)/(b^5×8):
(16 b^7 c^0)/(8 b^5)
16/8 = (8×2)/8 = 2:
(2 b^7 c^0)/b^5
Combine powers. (2 b^7 c^0)/b^5 = 2 b^(7 - 5) c^0:
2 b^(7 - 5) c^0
7 - 5 = 2:
2 b^2 c^0
c^0 = 1:
2×1 b^2
Write 2 b^2×1 as 2 b^2:
Answer: 2 b^2
Answer Link
21sberman 21sberman
  • 09-11-2017
(2b^12)/(a^3)
The c is no longer in the equation cause anything to the zero power is one.
Answer Link

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