ralph15
ralph15
06-10-2017
Mathematics
contestada
-3(4x+3)+4(6x+1)=43
Respuesta :
penfila11Pen
penfila11Pen
06-10-2017
-3(4x+3) + 4(6x+1) = 43
(-3{4x}) + (-3{3}) + (4{6x}) + (4{1}) = 43
(-12x) + (-9) + (24x) + (4) = 43
add like terms
(-12x + 24x) + (-9 + 4) = 43
(12x) + (-5) = 43
take -5 to the other side, this is possible by canceeling -5 with +5
12x - 5 + 5 = 43 + 5
12x = 48
to find x divide by 12 on both sides
[tex] \frac{12x}{12} [/tex] = [tex] \frac{48}{12} [/tex]
x = 4
check:
-3(4{4} + 3) + 4(6{4} + 1) = 43
-3(16 + 3) + 4(24 + 1) = 43
-3(19) + 4(25) = 43
-57 + 100 = 43
43 = 43
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