Respuesta :

konrad509
[tex](x-h)^2+(y-k)^2=r^2\\ \text{center}=(h,k)\\\\ (x+5)^2+(y-8)^2=1\\ \text{center}=(-5,8)[/tex]
TSO
[tex](x+5)^2 +(y-8)^2 = 1[/tex]

[tex](x-h)^2 +(y-k)^2 = r^2[/tex]

then the center of the circle is 

[tex](h,k)[/tex]

So the center of the circle for your question would be:

(-5, 8)

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