pyrexbatmanmonk4320 pyrexbatmanmonk4320
  • 07-09-2017
  • Mathematics
contestada

Find a point on the y-axis that is equidistant from the points (7, −7) and (1, 1).

Respuesta :

ghanami
ghanami ghanami
  • 07-09-2017
hello : 
a point on the y-axis is : P( 0, y)
PA = PB  or  PA² = PB².... A(7, -7)    B(1,1)
(7-0)²+(-7-y)² = (1-0)² + (1-y)²
49+49+14y+y² = 1+1-2y+y²
16y = - 96
y= - 6 
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