CamELlin9912 CamELlin9912
  • 06-03-2024
  • Mathematics
contestada

What value of k ensures that the system of equations x² −k=5 and 3x+4y=1 has no solution?
a) k = -5
b) k = 5
c) k = 6
d) k = -6

Respuesta :

icetornato
icetornato icetornato
  • 06-03-2024
Answer:
b) k = 5

Explanation:
For the system to have no solution, the first equation should represent a line that does not intersect with the line represented by the second equation. This occurs when the discriminant of the quadratic equation is negative. For x^2 - k = 5, the discriminant is (-k - 20). For no solution, (-k - 20) < 0. Solving for k gives k > -20, so k = 5 ensures no solution.
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