stephmhernandez12 stephmhernandez12
  • 07-01-2024
  • Mathematics
contestada

Suppose P(E) = 27⁄50 , P(Fc ) = 11⁄20 , and P(F ∩ Ec ) = 7⁄25. Find P(E ∪ F).

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ytas
ytas ytas
  • 07-01-2024

Answer:

To find \(P(E \cup F)\), you can use the inclusion-exclusion principle:

\[ P(E \cup F) = P(E) + P(F) - P(E \cap F) \]

Given \(P(E) = \frac{27}{50}\), \(P(F^c) = \frac{11}{20}\), and \(P(F \cap E^c) = \frac{7}{25}\), you need to find \(P(F)\) first.

\[ P(F) = 1 - P(F^c) \]

Substitute this into the inclusion-exclusion formula to find \(P(E \cup F)\).

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