cjmcgee1973 cjmcgee1973
  • 10-03-2017
  • Mathematics
contestada

Factor completely 3a4y3 − 12a3y2 + 6a2y.
3(a4y3 − 4a3y2 + 2a2y)
3a2y(a2y2 − 4ay + 2)
3y(a4y2 − 4a3y + 2a2)
Prime

Respuesta :

Аноним Аноним
  • 10-03-2017
3a4y3 − 12a3y2 + 6a2y
=3a^2y (a^2y^2 - 4ay + 2)

answer is 
3a^2y (a^2y^2 - 4ay + 2) (second choice)
Answer Link
SerenaBochenek SerenaBochenek
  • 20-02-2019

Answer:

The answer is [tex]3a^2y(a^2y^2-4ay+2)[/tex]

Step-by-step explanation:

Given the expression [tex]3a^4y^3-12a^3y^2+6a^2y[/tex]

We have to factor the above expression.

[tex]3a^4y^3-12a^3y^2+6a^2y[/tex]

Taking [tex]3a^2y[/tex] common from each term, we get

⇒ [tex]3a^2y(a^2y^2-4ay+2)[/tex]

Hence, the correct option is second.

Answer Link

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