RuteRod
RuteRod RuteRod
  • 11-02-2017
  • Mathematics
contestada

How would you solve this problem?

How would you solve this problem class=

Respuesta :

geerky42
geerky42 geerky42
  • 11-02-2017
Square both sides:

2s + 8 = s²

0 = s² - 2s - 8

Now factor:

0 = (s-4)(s+2)

s - 4 = 0 OR s + 2 = 0

s = 4 OR s = -2

Since square root cannot be negative, s = -2 is not possible,
so we are left with s = 4
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miner3mj
miner3mj miner3mj
  • 11-02-2017
Square both sides to find 2s +8 = s^2 and then subtract so it would be s^2 -2s -8 = 0. Then you factor to get (s-4)(s+2)=0 and get s={-2,4} then you check for answers that are extraneous and find that -2 is an extraneous answer which means s=4
Answer Link

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