The distance traveled in 10 sec is 250m
Given:
Initial velocity, u = 0
Acceleration, a = 5 m/s2
Time elapsed is t = 10 seconds
The distance traveled in 10 seconds by the particle when accelerating at 5 m/s2 is given by,
[tex]x= ut + \frac{1}{2} at^{2}[/tex]
Putting the values,
x= 0 x 10 + [tex]\frac{1}{2} (5) (10)^{2}[/tex]
x= 250 m
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