The sum of the first 13 terms is 260
How to calculate the sum of the first 13 terms ?
The first term(a) is 2
The common difference(d) is 3
n= 13
The formular is
n/2(2a + (n-1)d)
= 13/2 [ 2(2) + (13-1)3]
= 6.5 [4 + 12(3)]
= 6.5 [4 + 36]
= 6.5(40)
= 260
Hence the sum of the first 13 terms is 260
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