Respuesta :

[tex]\bf f(x)=\cfrac{1}{2}x+4\qquad inverse\implies x=\cfrac{1}{2}f(x)+4 \\\\ \textit{now, solving for f(x)} \\\\ x-4=\cfrac{f(x)}{2}\implies 2(x-4)=f(x)\iff f^{-1}(x) \\\\ f^{-1}(4)=2(\boxed{4}-4)\implies f^{-1}(4)=2(0)\implies f^{-1}(4)=0[/tex]