kcmaese
kcmaese
07-02-2017
Mathematics
contestada
how to solve 8x^3-27=0
Respuesta :
alexisfleming60
alexisfleming60
07-02-2017
Factor using difference of cubes, and set each factor equal to 0.
x=(-3+3i\sqrt(3))/(4),(-3-3i\sqrt(3))/(4),(3)/(2)
Answer Link
mohamedjamal
mohamedjamal
07-02-2017
8x³-27=0
8x³=27
x³=27/8
x=∛27/∛8
x=3/2
Answer Link
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