Respuesta :

konrad509

[tex]\dfrac{x^2+12x+35}{3x+15}=\dfrac{x^2+12x+35}{3(x+5)}=\dfrac{x^2+5x+7x+35}{3(x+5)}=\dfrac{x(x+5)+7(x+5)}{3(x+5)}=\\=\dfrac{(x+5)(x+7)}{3(x+5)}=\dfrac{x+7}{3}[/tex]

Answer:

(x+7) / 3

Step-by-step explanation:

Factorise the Top half to give  :

x² + 12x+ 35 = (x+5)(x+7)

Factorise the bottom half to give :  

3(x+5)

Cancel (x+5) from top and bottom to give :

(x+7) / 3

So our final answer is Option 3

Hope this helped and have a good day