Respuesta :

Answer: x = 0; x=10

Step-by-step explanation:

[tex]\frac{x+2}{x-4} *\frac{3x}{x+4}\\ \\x+2(x+4) = x-4(3x)\\x^{2} +2x+ 4x + 8 = 3x^{2} -12x\\2x+4x+12x =3x^{2} - x^{2} \\20x= 2x^{2} \\10x = x^2\\x=0\\x=10[/tex]

Hope this helps!

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