Step-by-step explanation:
Given the following question:
[tex](x-2)^2+(y-2)^2=9[/tex]
First thing we need to keep in mind is the fact that this graph is indeed a circle. We know this because we are adding two cubic roots to each other which makes the graph a circle. We know the two separate functions are cubic roots because they each have an exponent of two. Not only is this function whose graph is a circle, but the midpoint of this circle is (2,2).
Hope this helps.
