maya9390 maya9390

07-03-2022
Chemistry

contestada

how many grams Kl are needed to prepare 100.mL of 0.55M solution?

Respuesta :

kennyfung55p4h4tf kennyfung55p4h4tf

07-03-2022

Answer:

Explanation:

100mL = 0.1L

0.55 M = mol/0.1 L

mol = 0.055 mol

molar mass of KI = 165.998 g

0.055 * 165.998 = 9.13 g of KI

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