Answer:
Let the side of square be a cm and radius of the circle be r cm
Give, r=12 cm
Area of the square =a2cm2
ΔABC is a right angled triangle.
Thus, by Pythagoras theorem, we have
AB2+BC2=AC2
⇒a2+a2=(2r)2
⇒2a2=4r2
⇒a2=2r2
⇒a2=2(12)2
⇒a2=2×144
=288cm2
Step-by-step explanation:
MARK ME AS A BRAINLIST
