express in coordinate pairs: (x,y)
h(3) = - 4 ⇒ 3,-4
h( - 2) = 16 ⇒ -2, 16
[tex]\tt slope=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{16-(-4)}{-2-3}=\dfrac{20}{-5}=-4[/tex]
equation:
[tex]\tt y-y_1=m(x-x_1)\rightarrow m=slope\\\\y+4=-4(x-3)\\\\y=-4x+8[/tex]
for h(2):
[tex]\tt y=-4(2)+8=0[/tex]
h(2) = 0
