ginac21389
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  • 11-01-2022
  • Chemistry
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A molecule contains 47.30 g mercury (Hg) and 16.70 (Cl). what is its empirical formula?

A molecule contains 4730 g mercury Hg and 1670 Cl what is its empirical formula class=

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arshia6446
arshia6446 arshia6446
  • 12-01-2022
Answer: B) HgCl2

Explanation:

Convert grams to moles for both elements by dividing the mass by it’s molar mass (Mr).
Hg- 47.30/201= 0.23 mols
Cl- 16.70/35= 0.47 mols

Now, divide the moles of both elements with the smallest number. The smallest number here is 0.23.
Hg- 0.23/0.23= 1
Cl- 0.47/0.23= 2.04 (since there is a 0 after the decimal we will forget the decimal and write the number as a whole.)

Empirical Formula= Hg1Cl2
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