[tex]12 - (8x - 20) < 12 <=> 12- 8x+20<12<=> -8x <12-20-12 \\<=>-8x <-20<=>8x>20<=>x>\frac{20}{8}=\frac{5}{2}[/tex]
ANSWER: x > 5/2
Ok done. Thank to me :>
Answer:
[tex]x = \frac{5}{2} [/tex]
Step-by-step explanation:
12-(8x-20)<12
12-8x+20<12
-8x<12-12-20
-8x<-20
divide both by negetive 8
x>5/2
x> 2.5
