[tex]\text{Given that,}\\\\f(x) = 2x+1,~~ g(x) = x^2\\\\\ \text{now,}\\\\f(g(x)) = g(f(x))\\\\\implies f(x^2) = g(2x+1)\\\\\implies 2x^2+1=(2x+1)^2\\\\\implies 2x^2+1= (2x)^2 +2\cdot 2x + 1\\\\\implies 2x^2 +1 = 4x^2 + 4x +1\\\\\implies 4x^2 -2x^2 +4x +1-1 =0\\\\\implies 2x^2 +4x =0\\\\\implies 2x(x+2)=0\\\\\implies 2x =0~~ \text{or}~~ x+2 =0\\\\\implies x =0 ~~~\text{or}~ x =-2\\\\\ \text{Hence,}~ x =0 ~\text{and} ~ x =-2~ \text{are the solutions.}[/tex]
