[tex] \frac{3}{x^2-7x+10}+2= \frac{x-4}{x-5} [/tex] if we factor (x²-7x+10) we get (x-5)(x-2) multiply bot sides by (x-5)(x-2) 3=(x-4)(x-2) 3=x²-6x+8 minus 3 both sides 0=x²-6x+5 what 2 numbers multily to 5 and add to -6? -5 and -1 0=(x-1)(x-5) set to zero x-1=0 x=1
