Answer:
This is the third equation of motion.
[tex]{ \rm{ {v}^{2} = {u}^{2} + 2as }}[/tex]
• Dimensions of velocity
[tex]{ \rm{velocity = \frac{distance}{time} }} \\ \\ { \rm{[velocity] = \frac{L}{T} }} \\ \\ { \rm{{[velocity] =LT {}^{ - 1} }}}[/tex]
• Dimensions of acceleration
[tex]{ \rm{[acceleration] = LT {}^{ - 2} }}[/tex]
Therefore, Answer is;
[tex]{ \rm{LT {}^{ - 1} = LT {}^{ - 1} + (2 \times LT {}^{ - 2} \times L) }} \\ \\ { \rm{LT {}^{ - 1} = 2LT {}^{ - 2}(T + L)}} \\ \\ { \boxed{ \rm{ \: \frac{T}{2} = L }}}[/tex]
