The answer would be 25200
Reason being because there is a number of ways when selecting (3 consonants out of 7) and (2 vowels out of 4)
= (7C3 x 4C2)
= 7 x 6 x 5 /3 x 2 x 1 x 4 x 3/ 2 x 1
= 210.
The number of groups each having 3 consonants and 2 vowels = 210.
Because each group contains 5 letters.
They have to be rearranged
5 letters among themselves = 5!
= 5 x 4 x 3 x 2 x 1
= 120.
Required number of ways = (210 x 120) = 25200.
