Respuesta :

prishagupta035

x²+5x+3+2x²+10x15 =0

x²+2x²+5x+10x+3+15=0

3x²+15x+18=0

3(x²+5x+6) =0 because 3 is common factor

3(x²+3x+2x+6) spill the middle term

3(x(x+3)+2(x+3) take the common factor from term

3(x+2) (x+3)

answer is 3(x+2) (x+3)

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