Respuesta :

Answer:

[tex](x + 7)(x - 4) \\ = { \tt{ {x}^{2} + 7x - 4x - 28 }} \\ = { \tt{ {x}^{2} + 3x - 28 }} \\ { \boxed{ \bf{g \: is \: 3}}}[/tex]

theleangreenbean

Answer:

g=3

Step-by-step explanation:

Hi there!

To find the value of g, we can expand the two binomials using the distributive property:

[tex](x+7)(x-4)\\= x(x-4)+7(x-4)\\= x^2-4x+7x-28\\= x^2+3x-28[/tex]

Therefore, the value of g that makes the equation true is 3.

I hope this helps!

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