Answer:
The force Ahman uses to lift the load is 40 N
Step-by-step explanation:
Given;
force applied to the load, F₂ = 200 N
distance moved by the load, d₂ = 5 m
let the effort applied by Ahman, = F₁
distance moved by the effort, d₁ = 25 m
Apply the principle of conservation of energy;
Input work (J) = Output work (J)
F₁d₁ = F₂d₂
F₁ = (F₂d₂) / d₁
F₁ = (200 x 5) / 25
F₁ = 40 N
The force Ahman uses to lift the load is 40 N
