Answer:
440cm³
Step-by-step explanation:
Area of trapezium base=
[tex] \frac{1}{2} \times (a + b) \times h[/tex]
[tex] \frac{1}{2} \times (8 + 14) \times 4[/tex]
[tex] \frac{1}{2} \times 22 \times 4 \\ = \frac{88}{2} \\ = 44 {cm}^{3} [/tex]
Volume=Area or trapezium x Height between trapezium ends
[tex] = 44 \times 10 \\ = 440 {cm}^{3} [/tex]
