Answer:
[tex]\huge\boxed{c=17\ ft}[/tex]
Step-by-step explanation:
Use the Pythagorean theorem:
[tex]leg^2+leg^2=hypotenuse^2[/tex]
We have:
[tex]leg=15ft\\leg=8ft\\hypotenuse=c[/tex]
Substitute:
[tex]c^2=15^2+8^2\\\\c^2=225+64\\\\c^2=289\to c=\sqrt{289}\to c=17(ft)[/tex]
