khysner10 khysner10
  • 06-05-2021
  • Mathematics
contestada

which equation has no real solutions?
a. -2x^2=-168
b. 4x^2+76=32
c. 25x^2=1
d. 43-x^2=12

Respuesta :

Аноним Аноним
  • 06-05-2021

Answer:

[tex]B. 4x^2+76=32[/tex]

Step-by-step explanation:

[tex]In ~ option~ B[/tex]

[tex]4x^2+76=32\\[/tex]

[tex]4x^2=-76+32[/tex]

[tex]4x^2=-44[/tex]

[tex]x^2=-44/4=-11[/tex]

[tex]x^2=-11[/tex]

A square of any real number can't be a negative integer.

So, Option B is your answer

[tex]--------------[/tex]

hope it helps..

have a great day!!

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