Answer:
222 g
Explanation:
First we convert 500.0 mL to L:
- 500.0 mL / 1000 = 0.500 L
Then we use the definition of molarity to calculate how many calcium chloride moles are required:
- Molarity = moles / liters
- Molarity * liters = moles
- 4.0 M * 0.500 L = 2.00 mol
Now we convert 2.00 moles of calcium chloride into grams, using its molar mass:
- 2.00 mol * 111 g/mol = 222 g
