Answer:
0.95g of Ag we can produce
Explanation:
To solve this question we have to convert the mass of silver nitrate (AgNO₃) to moles. The moles of silver nitrate = Moles of Ag. Then, with molar mass of Ag we can know the mass of silver:
Moles AgNO₃ -Molar mass: 169.87g/mol-:
1.5g * (1mol / 169.87g) = 0.0088 moles Ag
Mass Ag -Molar mass: 107.87g/mol-:
0.0088 moles Ag * (107.87g / mol) =
0.95g of Ag we can produce
