Answer:
93 moles
Explanation:
1 mole of CaCO_3 will have 6.022×10^(23) molecules of CaCO_3 .
Given number of molecules of Calcium carbonate = 5.60 x 10^(25)
Therefore, number of moles n = [tex]\frac{5.60\times10^{25}}{6.022\times10^{23}}[/tex]
n= 93 moles
