juweria2005
juweria2005 juweria2005
  • 08-02-2021
  • Chemistry
contestada

The emf of the cell:
Ni/Ni^+2 (1.0 M) // Au^+3 (1.0 M)/ Au (E°= -0.25 V for Ni^+2/Ni; E°= 1.5 V for Au^+3/Au) is =
A) 1.25v
B) -1.25v
C) 1.75v
D) 2.0v
please help me
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Respuesta :

amandadiamondd amandadiamondd
  • 08-02-2021
The answer is B ...


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