Respuesta :

Answer:

[tex]1.28 \times 10 ^{-3} m^3/s[/tex]

Explanation:

Given that the radius of the pipe, r =0.0112 m

So, the area of the cross-section, [tex]a= \pi (0.0112)^2 = 3.941\times 10^{-4} m^2[/tex]

Speed of water in the pipe, v=3.25 m/s

Volume flow rate =[tex]av= 3.941\times 10^{-4} \times 3.25 = 1.28\times 10 ^{-3} m^3/s[/tex]

Hence, the volume flow rate is [tex]1.28 \times 10 ^{-3} m^3/s[/tex]

Answer:

For Acellus the answer is 0.00128

Explanation:

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