Answer:
4.46 °C
Explanation:
Step 1: Given and required data
- Energy absorbed (Q): 4430 J
- Specific heat of water (c): 4.186 J/g.°C
Step 2: Calculate the temperature change
We will use the following expression.
Q = c × m × ΔT
ΔT = Q / c × m
ΔT = 4430 J / (4.186 J/g.°C) × 237 g
ΔT = 4.46 °C
The temperature change is 4.46 °C.
