Answer:
The answer is B
[tex]y<-\frac{1}{4} x+2\\[/tex]
Step-by-step explanation:
Let:
[tex](x1,y1)=(0,2)\\(x2,y2)=(4,1)\\m=\frac{1-2}{4-0}=-\frac{1}{4} \\y-y1=m(x-x1)\\y-2=-\frac{1}{4} (x-0)[/tex]
Since the line is dotted and the area is below the line:
[tex]y<-\frac{1}{4}x+2[/tex]
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