Answer:
[tex]3v^2\left(5v^6-7v^3\right)=15v^8-21v^5[/tex]
Step-by-step explanation:
Given the expression
[tex]3v^2\left(5v^6-7v^3\right)[/tex]
Apply the distributive law
[tex]a\left(b-c\right)=ab-ac[/tex]
[tex]a=3v^2,\:b=5v^6,\:c=7v^3[/tex]
[tex]=3v^2\cdot \:5v^6-3v^2\cdot \:7v^3[/tex]
[tex]=3\cdot \:5v^6v^2-3\cdot \:7v^3v^2[/tex]
[tex]=15v^8-21v^5[/tex]
Thus, we conclude that
[tex]3v^2\left(5v^6-7v^3\right)=15v^8-21v^5[/tex]
