Seudónimo Seudónimo
  • 07-10-2016
  • Mathematics
contestada

can anybody tell me the answer to this im so confused

can anybody tell me the answer to this im so confused class=

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apologiabiology
apologiabiology apologiabiology
  • 07-10-2016
meh

ok so when have sqrt, try to square both sides
[tex] \sqrt{2x-1}=2+ \sqrt{x-4} [/tex]
square both sides
[tex] 2x-1=4+4 \sqrt{x-4}+x-4 [/tex]
[tex]2x-1=x+4 \sqrt{x-4} [/tex]
mnus x both sides
[tex]x-1=4 \sqrt{x-4} [/tex]
square oth sides
x^2-2x+1=16(x-4)
x^2-2x+1=16x-64
minus (16x-4) from both sides
x^2-18x+65=0
factor
(x-5)(x-13)=0
set each to zero
x-5=0
x=5

x-13=0
x=13

x=5 and 13

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