This written in simple terms is basically that the distance between 1 point and (-5, 60) is 61.
So if the point is on the [tex]x[/tex] axis, then we know the [tex]y[/tex] value would be a [tex]0[/tex].
So we find a coordinate with [tex](x, 0)[/tex] which is 61 units away from the point [tex](-5, 50)[/tex]. So using the distance formula: [tex]\sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2}[/tex], we substitute the values. [tex]\sqrt{(x + 5)^2 + (0 - 60)^2}[/tex].
