Answer: [tex](x+3)^{2} +(y+15)^{2}=260[/tex]
Step-by-step explanation:
The centre is (-3,-15), so we can say the equation of circle is [tex](x+3)^{2} +(y+15)^{2}=r^{2}[/tex]. put (5,-1) at this equation.
then, we can know [tex]r^{2}=260[/tex].
∴ [tex](x+3)^{2} +(y+15)^{2}=260[/tex]
