Answer:
the final concentration of HCl is 3.72 M
Explanation:
Given that;
V1 = 922.0 mL, M1 = 4.73 M
V2 = 549.0 mL, M2 = 2.03 M
so final concentration of HCL
= (( M1V1) + (M2V2)) / (V1 + V2)
(( 4.73 × 922.0)) + (2.03 × 549.0)) / (922.0 + 549.0)
= 5475.53 / 1471.0
= 3.7223 ≈ 3.72 M
Therefore the final concentration of HCl is 3.72 M
