JSC990 JSC990
  • 08-10-2020
  • Mathematics
contestada

Determine the solution for x^2-3x-28 > or equal to 0

Respuesta :

mariag1512 mariag1512
  • 08-10-2020
The solutions are:
x = −4,x = 7
Explanation:
X^2−3x−28= 0
We can first factorise this expression by splitting the middle term and then find the solutions:
= x^2−7x+4x−28=0

= x( x−7) + 4( x − 7)=0
=(x+4)(x−7)
Now, we can equate the two factors with zero and find the solutions:
x+4=0,x =−4x−7=0,x=7
Answer Link
chloebellagirl chloebellagirl
  • 10-02-2021

Answer:

C (-∞, -4] [7,∞)

Answer Link

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